Question

A 200g ball begins falling from a height of 15m. If the (a) acceleration due to gravity is 10 m/s^2. How long do you calculate it will be before the object reaches the ground? Which formula will you use?

Answer 1

1.732 seconds

`s=ut+(1)/(2)at^2`

Step-by-step explanation:

s = Displacement of ball = 15 m

g = a = Acceleration due to gravity =
`10\ \text{m/s}^2`

u = Initial velocity of the ball = 0

t = Time taken

From the kinematic equations we use the following formula

`s=ut+(1)/(2)at^2\\\Rightarrow 15=0t+(1)/(2)* 10t^2\\\Rightarrow t=\sqrt{(15* 2)/(10)}\\\Rightarrow t=√(3)=1.732\ \text{s}`

The object will reach the ground after 1.732 seconds.

The formula used is
`s=ut+(1)/(2)at^2`.