Question

Lindsay went for a drive. she used 8/3 gallon of gas every 4/5 of an hour. solve for her gallons per hour

Answer 1

A = amount of gas used for the drive = 8/3 gallon

t = duration of time in which amount of gas A is used = 4/5 hours

r = rate of gas used

rate of use of gas is given as the ratio of gas used in the amount of time given.

hence , rate of gas used is given as

R = A/t

inserting the values given above

R = (8/3)/(4/5)

R = 8 x 5/(3 x 4)

R = 40/12

R = 3.33 gallons per hour

Answer 2

Given that Lindsay went for a drive. she used
`(8)/(3)` gallon of gas every
`(4)/(5)` of an hour. Now we need to solve for her gallons per hour.

To find value for 1 unit for any similar problem we just divide one quantity by another quantity

so we will use same logic here

`(4)/(5)` of an hour uses
`(8)/(3)` gallon of gas

then 1 hour uses \frac{\left(\frac{8}{3}\right)}{\left(\frac{4}{5}\right)} gallon of gas

=
`(8)/(3)\cdot(5)/(4)`

=
`(40)/(12)`

=
`(10)/(3)`

Hence final answer is
`(10)/(3)` gallons per hour.