What is the density of ammonia (NH3) at 293 K and 0.913 atm?

Question

asked Jul 21, 2019 41.7k views

2 Answers

Tbhartman · Answer 1 · 2019-07-28T14:27:24+0000

Answer : The density of ammonia is 0.6464 g/L.

Solution : Given,

Temperature of ammonia = 293 K

Pressure of ammonia = 0.913 atm

Molar mass of ammonia = 17.031 g/mole

By using ideal gas law,

$PV=nRT\\P=(wRT)/(MV) \\P=(\rho RT)/(M)\\\rho=(PM)/(RT)$

where,

P = pressure of gas

V = volume of gas

n = number of moles

T = temperature of gas

R = Gas constant = 0.0821 Latm/mole/K

$\rho$ = Density

$(Moles=\frac{Mass}{\text{ Molar mass}})$ and
(Density=(Mass)/(Volume))

Now put all given values in ideal gas law, we get

$\rho=((0.913atm)* (17.031g/mole))/((0.0821Latm/mole/K)* (293K))=0.6464g/L$

Therefore, the density of ammonia is 0.6464 g/L.