Question

HELP WITH THESE QUESTIONS PART 2... 1 Question

Answer 1

Explanation and Answers:

`((1)/(√(10)),(3)/(√(10)))` is in the format (cos, sin). So, adjacent = 1, opposite = 3, hypotenuse =
`√(10)`

sin =
`(opposite)/(hypotenuse)` =
`(3)/(√(10))((√(10))/(√(10)))` =
`(3√(10))/(10)`

cos =
`(adjacent)/(hypotenuse)` =
`(1)/(√(10))((√(10))/(√(10)))` =
`(√(10))/(10)`

tan =
`(opposite)/(adjacent)` =
`(3)/(1)` = 3

csc =
`(hypotenuse)/(opposite)` =
`(√(10))/(3)`

sec =
`(hypotenuse)/(adjacent)` =
`(√(10))/(1)` =
`√(10)`

cot =
`(adjacent)/(opposite)` =
`(1)/(3)`