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Question 17

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Find the sum of the first 10 terms of the following geometric sequences:
{3, 6, 12, 24, 48...}
3069
3066
O
3072
O 3075

User Bretik
by
4.9k points

1 Answer

8 votes

Answer:


S_(10) = 3069

Explanation:

Given


Sequence = \{3, 6, 12, 24, 48...\}

Required

Determine the sum of the first terms

First, we calculate the common ratio (r)


r = (T_2)/(T_1)


r = (6)/(3)


r = 2

The required sum is:


S_n = (a(r^n-1))/(r-1)

Substitute 3 for a, 2 for r and 10 for n


S_(10) = (3(2^(10)-1))/(2-1)


S_(10) = (3(1024-1))/(2-1)


S_(10) = (3(1023))/(2-1)


S_(10) = (3(1023))/(1)


S_(10) = (3069)/(1)


S_(10) = 3069

User Alexandre  Rozier
by
4.8k points
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