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PLEASE HELP WHICH ONE IS IT AND CAN YOU EXPLAN HOW YOU GOT THE ANSWERS TY!!!

In a titration, a 20 mL sample of NaOH(aq) was neutralized by 14.9 mL of 0.13 mol/L
H2SO4(aq). The concentration of the base is
A)8.7 mol/L
B)10.048 mol/L
C)0.19 mol/L
D)0.35 mol/L
/L

1 Answer

5 votes

Answer:

C)0.19 mol/L .

Step-by-step explanation:

Hello!

In this case, since the chemical reaction between sodium hydroxide and sulfuric acid is:


H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

Whereas a 1:2 mole ratio is seen between the acid and the base, we can write:


2*M_(acid)V_(acid)=M_(base)V_(base)

In such a way, we solve for the concentration of base and plug in to obtain:


M_(base)=(2*M_(acid)V_(acid))/(V_(base)) \\\\M_(base)=(2*0.13mol/L*14.9mL)/(20mL) \\\\M_(base)=0.19mol/L

Thus, the answer is C)0.19 mol/L

Best regards!

User Hellojeffy
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