Answer:
Area of the shaded region = 16(π - 2) in²
Perimeter of the shaded region = 4(π +
) in
Explanation:
Since, BDC is a quarter of the circle with radius = 8 in.
Area of the quarter of the circle =
=
= 16π in²
Area of ΔBCD =
=
= 32 in²
Since, area of the shaded part = Area of quarter of the circle - Area of triangle BCD
= (16π - 32)
= 16(π - 2) in²
Therefore, area of the shade region = 16(π - 2) in²
Similarly, length of arc BD =
=
= 4π in.
Length of the diagonal of a square = (Side)√2
= 8√2 in
Perimeter of the shaded region = Length of arc BD + Length of diagonal BD
= 4π + 8√2
= 4(π + 2√2) in.