Question

What are the solutions of x^2 = -7x-8

Answer 1

`Solution, solve\:for\:x,\:x^2=-7x-8\quad :\quad x=(-7+√(17))/(2),\:x=(-7-√(17))/(2)`

`Steps:`

`x^2=-7x-8`

`\mathrm{Add\:}8\mathrm{\:to\:both\:sides},\\x^2+8=-7x-8+8`

`\mathrm{Simplify},\\x^2+8=-7x`

`\mathrm{Add\:}7x\mathrm{\:to\:both\:sides},\\x^2+8+7x=-7x+7x`

`\mathrm{Simplify},\\x^2+7x+8=0`

`Solve\:with\:the\:quadratic\:formula,\\\mathrm{For\:}\quad a=1,\:b=7,\:c=8:\quad x_(1,\:2)=(-7\pm √(7^2-4\cdot \:1\cdot \:8))/(2\cdot \:1),\\x=(-7+√(7^2-4\cdot \:1\cdot \:8))/(2\cdot \:1):\quad (-7+√(17))/(2),\\x=(-7-√(7^2-4\cdot \:1\cdot \:8))/(2\cdot \:1):\quad (-7-√(17))/(2)`

`\mathrm{The\:final\:solutions\:to\:the\:quadratic\:equation\:are:},\\x=(-7+√(17))/(2),\:x=(-7-√(17))/(2)`

`\mathrm{Hope\:This\:Helps!!!}`

`\mathrm{-Austint1414}`