Cobaltâ’60 is a radioactive isotope used to treat cancers of the brain and other tissues. A gamma ray emitted by an atom of this isotope has an energy of 4.70 MeV (million elect…

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asked Aug 21, 2019 151k views

1 Answer

Alijvhr · Answer 1 · 2019-08-27T06:49:33+0000

Energy of gamma rays is given by equation

$E = h\\u$

here we know that

h = Planck's constant

$\\u = frequency$

now energy is given as

E = 4.70 MeV = 4.70 * 10^6 * 1.6 * 10^(-19)

E = 7.52 * 10^(-13) J

now by above equation

$E = h\\u$

$7.52 * 10^(-13) = 6.6 * 10^(-34) \\u$

$\\u = 1.14 * 10^(21) Hz$

now for wavelength we can say

$\lambda = (c)/(\\u)$

$\lambda = (3* 10^8)/(1.14 * 10^(21))$

$\lambda = 2.63 * 10^(-13) m$