Question

Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 Ă— 10-13. Determine the molar solubility of AgBr in a solution containing 0.150 M NaBr. Ksp (AgBr) = 7.7 Ă— 10-13. 5.1 Ă— 10-12 M 3.9 Ă— 10-13 M 0.150 M 5.8 Ă— 10-5 M 8.8 Ă— 10-7 M

Answer 1

Hey there!:

Given the reaction:

NaBr ⇌ Na⁺ + Br⁻

↓ ↓ ↓

0.150M 0.150M 0.150M

AgBr ⇌ Ag⁺ + Br⁻

↓ ↓ ↓

x x 0.150M

Therefore:

Ksp = x * 0.150

x = ( 7.7 * 10⁻¹³ ) / 0.150

x = 5.1 * 10⁻¹²

Answer B

Hope that helps!