Question

It requires a force of 100 N to stretch a spring of negligible mass by a distance of 0.1 m. If the spring instead stretches a distance of 0.25 m, how much force was applied to it?

answer choices
1. 200 N
2. 300 N
3. 250 N
4. 100 N
5. 175 N
6. 325 N
7. 150 N
8. 225 N
9. 275 N

Answer 1

by the formula of spring force we know that

`F = kx`

here we know that

`F = 100 N`

`x = 0.1 m`

now we will have

`100 = k * 0.1`

`k = 1000 N/m`

now by similar way if the stretch in spring is 0.25 m

force is given by

`F = kx`

`F = 1000 * 0.25`

`F = 250 N`

so it will require F = 250 N force

Answer 2

Answer: The force applied on the spring is 250 N

Step-by-step explanation:

To calculate the spring constant, we use the equation:

`F=kx` ......(1)

where,

F = force exerted on the spring = 100 N

k = spring constant = ?

x = length of the spring = 0.1 m

Putting values in equation 1, we get:

`100N=k* 0.1m\\\\k=(100N)/(0.1m)=1000N/m`

Now, calculating the force exerted on the spring, we use equation 1:

We are given:

`k=1000N/m\\x=0.25m`

Putting values in above equation, we get:

`F=1000N/m* 0.25m\\\\F=250N`

Hence, the force applied on the spring is 250 N