Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point. Hurry Please!

y-3=-1/5(x+2); (-2,7)

A. y=5x+7
B. y=5x+17
C. y=(1/5)x-2
D. y=-2x+3

Answer 1

y = 5x + 17 (Answer B)

Explanation:

We are given in point slope form the equation of a line: y - 3 = (-1/5)(x + 2). Directly from this equation we can find the slope: -1/5.

The slope of any line perpendicular to the given line is the negative reciprocal of the slope of the given line: Here it is +5.

Using the slope-intercept formula y = mx + b, we replace y with 7, x with -2 and m with 5, obtaining:

7 = 5(-2) + b, which simplifies to 7 = -10 + b. Thus, b = 17.

The desired equation is thus y = 5x + 17 (Answer B)