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A line passes through the point (6,-6) and has a slope of 3 over 2

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assuming you meant what is its slope-intercept form.



\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies \cfrac{3}{2} \\\\\\ \begin{array} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=\cfrac{3}{2}(x-6) \\\\\\ y+6=\cfrac{3}{2}x-9\implies y=\cfrac{3}{2}x-15

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