Question

Simply the rational expression.state any restrictions on the variable. k2-k-2/k2-4k-5

Answer 1

We are given

`(k^2-k-2)/(k^2-4k-5)`

Firstly, we will factor numerator and denominator

`(k^2-k-2)/(k^2-4k-5)=((k-2)(k+1))/((k-5)(k+1))`

Restrictions:

we know that denominator can not be zero

so, we can set denominator =0

and solve for k to get restrictions

`(k-5)(k+1)=0`

`k=-1,k=5`

Simplification:

`(k^2-k-2)/(k^2-4k-5)=((k-2)(k+1))/((k-5)(k+1))`

we can see that k+1 gets cancelled

so, we get

`(k^2-k-2)/(k^2-4k-5)=((k-2))/((k-5))`..........Answer