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Answer:
81a^4b^12
Explanation:
(-3)^4 = 3^4 = 81;
(a)^4 = a^4; and
(b^3)^4 = b^12.
Putting all this together, we obtain 81a^4b^12.
You have to power all the values in the brackets, like such:
(-3ab^3)^4 = (-3)^4 * a^4 * (b^3)^4 = 81*a^4*b^12
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