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Megan walks 1100\,\text m1100m1100, start text, m, end text to the left in 330\,\text s330s330, start text, s, end text. What was her average speed in \dfrac{\text m}{\text s} s m ​ start fraction, start text, m, end text, divided by, start text, s, end text, end fraction?

User Don Li
by
2.9k points

2 Answers

4 votes

Answer:

33.3

Step-by-step explanation:

User Gerardo Lima
by
3.1k points
4 votes

Answer:

v = 3.34 m/s

Step-by-step explanation:

Given that,

Distance, d = 1100 m

Time, t = 330 s

We need to find the average speed of the Megan. It is equal to the total distance divided by total time taken.


v=(1100\ m)/(330\ s)\\\\v=3.34\ m/s

So, the average speed of Megan is 3.34 m/s.

User Steve Burns
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3.6k points