Factor completely. 2x^2y + 2xy + 4x + 4 A. (2x + 4)(xy + 1) B. (2x + 4y)(x + 1) C. 2(xy + 2)(x + 1) D. (2xy + 4)(x + 1)

asked Jan 28, 2019 164k views

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6 votes

Answer:

2(xy + 2)(x + 1) (C)

Explanation:

2x^2y + 2xy + 4x + 4

= 2xy(x + 1) + 4(x + 1)

= (2xy + 4)(x + 1)

= 2(xy + 2)(x + 1)

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