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Factor completely. 2x^2y + 2xy + 4x + 4 A. (2x + 4)(xy + 1) B. (2x + 4y)(x + 1) C. 2(xy + 2)(x + 1) D. (2xy + 4)(x + 1)

User Tom Tanner
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1 Answer

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Answer:

2(xy + 2)(x + 1) (C)

Explanation:

2x^2y + 2xy + 4x + 4

= 2xy(x + 1) + 4(x + 1)

= (2xy + 4)(x + 1)

= 2(xy + 2)(x + 1)

User Arkadiusz Drabczyk
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