Question

PLEASE HELP NOW 20pts........

As people entered the gym for the basketball tournament, members of the pep club were selling raffle tickets. They had $1.50 tickets and $5 tickets. The number of $1.50 tickets sold was two less than four times the number of $5 tickets sold, and the pep club raised $1,152 from the ticket sales. Let x represent the number of $1.50 tickets sold and let y represent the number of $5 tickets sold. check all the correct answers

Answer 1

A & D

Explanation:

As people entered the gym for the basketball tournament, members of the pep club were selling raffle tickets. They had $1.50 tickets and $5 tickets. The number of $1.50 tickets sold was two less than four times the number of $5 tickets sold, and the pep club raised $1,152 from the ticket sales. Let x represent the number of $1.50 tickets sold and let y represent the number of $5 tickets sold.

Which equations best represent the situation? Check all that apply.

x = 4y – 2

1.5x + 5y = 1152

Answer 2

number of tickets of $5 sold = 418 and number of tickets of $1.5 sold = 105

Explanation:

Let y be the number of $5 tickets sold and x be the number of $1.50 tickets sold.

Now from the statement " Number of $1.50 tickets sold was 2 less than the four times the number of $5 tickets sold".

Equation will be x = 4y - 2

4y - x = 2 ---------(1)

For second equation statement is " The pep club raised $1152 from the ticket sales".

Equation will be 5y + (1.50)x = 1152 -------(2)

Now we multiply equation (1) by 1.5 and add it to equation (2)

6y - 1.5x + (5y + 1.5x) = 3 + 1152

11y = 1155

y = 105

Now we put y = 105 in equation (1)

x = 4×105 - 2

x = 420 -2

x = 418

Therefore, number of tickets of $5 sold = 418 and number of tickets of $1.5 sold = 105