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V(t)=t^2+2 (m/s)
For t=0, x(0)=4m
Find the acceleration and the kinematic equation

User Benkiefer
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1 Answer

6 votes

Acceleration can be found by differentiating v(t) by t:

dv/dt =d(t^2+2)/dt

=d(t^2)/dt + d(2)/dt

=2tdt/dt + 0

=2t

The displacement x(t) can be found by integrating v(t) by t

x(t) = int(t^2 + 2)dt

= t^3/3 + 2t + c

When t=0, x(0)=4=0+0+c

So c=4

x(t) = t^3/3 + 2t + 4

v(t) = t^2 + 2

a(t) = 2t


User Aaron Blenkush
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