226k views
5 votes
Write the equation of the line passing through the points (-5,3) and (1,-3) in slope intercept form. SHOW WORK!

User Nlloyd
by
8.3k points

1 Answer

7 votes

Any straight line on the coordinate plane can be described by the equation

y=mx+b

Where:

x,y are the coordinates of any point on the line

m is the slope of the line

b is the intercept (where the line crosses the y-axis) .

The slope m can be found beetween two points:


m=(y_2-y_1)/(x_2-x_1)  = (-3-3)/(1-(-5)) = -1

m and one of the known points is inserted in the equation y=mx+b


3=-1*-5+b
1\cdot \:5+b=3
5+b-5=3-5
b=-2

Then the equation is:

y = mx + b ⇒
y=-x-2

User Jason Fritcher
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories