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Write the equation of the line passing through the points (-5,3) and (1,-3) in slope intercept form. SHOW WORK!

User Nlloyd
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1 Answer

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Any straight line on the coordinate plane can be described by the equation

y=mx+b

Where:

x,y are the coordinates of any point on the line

m is the slope of the line

b is the intercept (where the line crosses the y-axis) .

The slope m can be found beetween two points:


m=(y_2-y_1)/(x_2-x_1)  = (-3-3)/(1-(-5)) = -1

m and one of the known points is inserted in the equation y=mx+b


3=-1*-5+b
1\cdot \:5+b=3
5+b-5=3-5
b=-2

Then the equation is:

y = mx + b ⇒
y=-x-2

User Jason Fritcher
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