Question

For the function f(x)=x2−24÷3+12

f(1)


​f(0)​


​f(−1)​

Answer 1

Put the values of x to the equation of the function.

`f(x)=(x^2-24)/(3)+12`

`f(1)=(1^2-24)/(3)+12=(1-24)/(3)+12=(-23)/(3)+12=-7(2)/(3)+12=4(1)/(3)\\\\f(0)=(0^2-24)/(3)+12=(-24)/(3)+12=-8+12=4\\\\f(-1)=((-1)^2-24)/(3)+12=(1-24)/(3)+12=(-23)/(3)+12=-7(2)/(3)+12=4(1)/(3)`