Question

It takes Tyler twice as long as Kyle to complete the same job. When the men work together, they can complete the job in 6 hours. How many hours are required for Tyler to do the job alone? Enter your answer in the box.

Answer 1

Tyler to do the job alone =18/1 = 18 hrs

Solution

It takes Tyler twice as long as Kyle to complete the same job.

efficiency of Kyle is twice the efficiency of Tyler

Let x be the efficiency of Tyler the efficiency of Kyle is 2x

efficiency of Tyler : efficiency of Tyler = x :2x =1:2

Therefore total efficiency = 1 + 2 =3x

The total job = efficiency x total time

Here total time to complete the job=6 hrs

Total job =18

Time taken to complete the job =Total job/efficiency

Tyler to do the job alone =18/1 = 18 hrs

Kyle to do the job alone =18/2 = 9 hrs

Answer 2

Answer: Time taken by Tyler to do the job alone =18 days.

Step-by-step explanation:

Since we have given that

Tyler takes twice as long as Kyle to complete the same job,

Let the work done by Kyle in 1 day be

`(1)/(x)`

Let the work done by Tyler in 1 day

`(1)/(2x)`

If the men work together , they can complete the work in 6 hours.

According to question, we get

`(1)/(x)+(1)/(2x)=(1)/(6)\\\\\implies (2+1)/(2x)=(1)/(6)\\\\\implies (3)/(2x)=(1)/(6)\\\\\implies x=9`

Hence, time taken by Kyle is x= 9 hours

and

Time taken by Tyler to do the job alone is given by

`2x=2* 9=18\ hours`