Question

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Solve for x.

Answer 1

Answer: x = 4

Explanation:

`√(x+12)` =
`√(x)` + 2

RESTRICTIONS: x + 12 ≥ 0 and x ≥ 0 → x ≥ 0 (because square roots cannot be negative)

`(√(x+12))^(2)` =
`(√(x) + 2)^(2)`

x + 12 = x + 4
`√(x)` + 4

-x -4 -x -4

8 = 4
`√(x)`

÷4 ÷4

2 =
`√(x)`

(2)² =
`(√(x))^(2)`

+/- 4 = x

Solutions: x = 4, x = -4 however, x = -4 is restricted so not valid