Question

What’s an equation of a line that’s perpendicular to 4x-16y=-8 and passes through the point (-3,3)

Answer 1

Let's first convert the equation of the line given to slope-intercept form:

`y=(1)/(4)x +(1)/(2)`

We know that the slope (m in y = mx + b) is 1/4. A perpendicular line always has a negative reciprocal slope. So, the equation of the perpendicular line in slope-intercept form is simply:

`y= -4x + (1)/(2)`

But, since they give us two points on the line, we'll put that equation in point-slope form (y - k = m(x - h)):

`y - 3 = -4(x+3)`

So, your final answer is y - 3 = -4(x + 3).

Answer 2

Answer: 4x - 16y = -60