Answer: x = 3
x = 2 is restricted (aka extraneous)
Explanation:
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RESTRICTIONS: x - 1 ≠ 0 → x ≠ 1 and x - 2 ≠ 0 → x ≠ 2 (because the denominator cannot equal zero)
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x(x - 2) - 1(x - 1) = 2x - 5
x² - 2x - x + 1 = 2x - 5
x² - 3x + 1 = 2x - 5
-2x +5 -2x +5
x² - 5x + 6 = 0
(x - 2)(x - 3) = 0
x - 2 = 0 x - 3 = 0
+2 +2 +3 +3
x = 2 x = 3 These are the solutions, but x = 2 is restricted