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Find 3 consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen

User MichaelB
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1 Answer

4 votes

Answer:

The three consecutive odd integers are 3,5,7

How:

Let x, (x+2),(x+4) represent the three consecutive odd integers

Question states***

2[x + (x+4)] = (x+2) + 15

solving for s

4x + 8 = x + 17

3x = 9

x = 3 The three consecutive odd integers are 3,5,7




User Mwjackson
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