Answer:
![2*2^(-3) * 2^(-5) =(1)/(128)](https://img.qammunity.org/2022/formulas/mathematics/high-school/pwpxvamrykzleq6ek6wv1tmdf3atjt0hx0.png)
Explanation:
Given
![2*2^(-3) * 2^(-5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/c9xsc9c1d93r7c5ydcs1b7s5ebge49s2zf.png)
Required
Write as a fraction
To do this, Jordan has to apply the following rules
Negative Exponent rule:
So, the expression is:
![2*2^(-3) * 2^(-5) = (2)/(2^3 * 2^5)](https://img.qammunity.org/2022/formulas/mathematics/high-school/cl4yjt9jgcxod5twp9tsgxgk71mduhajrw.png)
To solve further, we apply the product rule of exponent
![a^m * a^n = a^(m+n)](https://img.qammunity.org/2022/formulas/mathematics/high-school/4n5kbzvyuo5az2c1w5snl4yai3dkjsrafz.png)
So, the expression is:
![2*2^(-3) * 2^(-5) =(2)/(2^(3+5))](https://img.qammunity.org/2022/formulas/mathematics/high-school/1fe60m3ohbm2h4macrf7kirdhz2sq2a5vr.png)
![2*2^(-3) * 2^(-5) =(2)/(2^8)](https://img.qammunity.org/2022/formulas/mathematics/high-school/4vcyojivvrda8p23vodo450ltbd3c8ac6m.png)
Evaluate the exponents
![2*2^(-3) * 2^(-5) =(2)/(256)](https://img.qammunity.org/2022/formulas/mathematics/high-school/jrhlui0eo53strr0gwwpd5gfq1af4b2o7y.png)
Divide the numerator and denominator by 2
![2*2^(-3) * 2^(-5) =(2/2)/(256/2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ypomsccqryqexcud0z27we726y37c5flc0.png)
![2*2^(-3) * 2^(-5) =(1)/(128)](https://img.qammunity.org/2022/formulas/mathematics/high-school/pwpxvamrykzleq6ek6wv1tmdf3atjt0hx0.png)