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One Solution, infinitely many, or no solutions? x-3y=27,2x=6y-14
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4 votes
One Solution, infinitely many, or no solutions?

x-3y=27,2x=6y-14

User Steve Saporta
by
8.1k points

1 Answer

2 votes
Ok, let’s take it step by step.
Take the first equation and solve for x.
x-3y=27
x=3y+27
Substitute x into the second equation.
2(3y+27)=6y-14
6y+68=6y-14
68=-14

Since 68 does not = -14, the system of equations has no solution.
User Slowyn
by
7.9k points
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