Question

A survey asked students whether they have any siblings and pets. the survey data are shown in the relative frequency table.

given that a student does not have a sibling, what is the likelihood that he or she has a pet?

Answer 1

D.

Explanation:

A pE x

Answer 2

The likelihood that he or she has a pet given that a student does not have a sibling is:

Option: D ( 60%)

Explanation:

Let A denote the event that a student does not have a sibling.

Let B denote the event that a students has a pet.

Then A∩B denotes the event that the student does not have a sibling but has a pet.

Let P denote the probability of an event.

Then, we are asked to find:

P(B|A)

We know that:

`P(B|A)=(P(A\bigcap B))/(P(A))`

Also from the table we have:

P(A)=0.25

and P(A∩B)=0.15

Hence,

`P(B|A)=(0.15)/(0.25)\\\\P(B|A)=(3)/(5)\\\\P(B|A)=0.6`

which in percentage is:

`0.6* 100=60\%`

Hence, the likelihood is:

60%