Question

9. Write the equation of a line that is PERPENDICULAR to 6x+3y=15 and passes

through the coordinate (12,-5).

Answer 1

y = 1/2x - 11

Explanation:

Step one convert to y = mx+b form

6x + 3y =15

Isolate Y

3y = -6x + 15

Divde the 3 among the other numbers

y = -2x + 5

That is the equation

perpindiculr to that is y = 1/2x + 5 but solve for the points and plug in

the points are (12,-5)

So -5 = 1/2 (12) +b

-5 = 6 + b

Solve for B

-5 - 6 = b

b = -11

FINAL EQUATION

y = 1/2x - 11