A 0.43-kg block sits on a lab table. There is a forward force of 5.57 N and a force backwards of 2.20 N. What is the acceleration of the block?

Andrey Tarantsov asked Oct 14, 2023

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A 0.43-kg block sits on a lab table. There is a forward force of 5.57 N and a force backwards of 2.20 N.

What is the acceleration of the block?

Andrey Tarantsov asked Oct 14, 2023

2.6k points

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10 votes

Answer:

7.84 m/s^2

Step-by-step explanation:

NET forward force = 5.57 - 2.20 N =3.37 N

F = ma

3.37 = .43 * a a = 7.84 m/s^2

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