Answer:
Summary:
Explanation:
We know that the diagonals of a parallelogram bisect each other.
As
The parallelogram PQRS is given, so
RT = TP
Given
plug in RT = x and TP = 5x-28 in the equation RT = TP
RT = TP
x = 5x-28
switch the sides
5x-28 = x
adding 28 in both sides
5x-28+28 = x+28
simplify
5x = x+28
subtract x from both sides
5x-x = x+28-x
4x = 28
divide boh sides by 4
4x ÷ 4 = 28 ÷ 4
simplify
x = 7
Therefore, we conclude that the value of x is: x = 7
Similarly,
QT = TS
Given
plug in QT = 5y and TS = 2y+12 in the equation QT = TS
QT = TS
5y = 2y+12
subtract 2y from both sides
5y - 2y = 2y+12-2y
simplify
3y = 12
divide both sides by 3
3y ÷ 3 = 12 ÷ 3
simplify
y = 4
Therefore, we conclude that the value of y is: y = 7
Summary: