141k views
3 votes
The population of a small town, P, as a function of time, t, in years past 1940 is given below.

P = 1,720 + 200t

For which of the following years was the population of the town 8,920?

User Doofus
by
8.4k points

2 Answers

1 vote

Answer:

1976

Explanation:

hope this helps

User EthernetCable
by
8.0k points
4 votes

Answer: 1976

Steps:

Let t* be the year in which the population reached a count of 8920. Solve for t*:


P=200t+1720\\8920=200t^*+1720\\7200=200t^*\\t^* = 36

The population grew to the number 8920 in 36 years past 1940, i.e., 1976

User Pierre Maoui
by
9.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories