Answer:
The mean increased by $1.5 and percent increase is 42.85%.
Explanation:
Formula for mean:

It is given that Grant spent $2.50, $4.00, $4.25, and $3.25 on breakfast one week.
Total money spent by him in first week is

Mean for first week is

The next week he spent $6 more in total for the 4 breakfasts than the week before.
Total money spent by him in second week is

Mean for second week is

Increase in mean

Therefore the mean increased by $1.5.
Percent increase in mean is


Therefore the mean increased by $1.5 and percent increase is 42.85%.