Question

Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = _____Ω 5.4 x 10-1 5.0 x 109 2.0 x 10-18 1.6 x 10-2

Answer 1

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030
`cm^2`

and specific resistance (ρ) =
`1.8 * 10^(-6)` ohm-cm.

Use the formula R=(Specific resistance*L)/A, to calculate the Resistance(R)

then,
`R=(1.8 * 10^(-6) * 270)/(0.030)` ohm

Simplify:

R = 0.0162 ohm =
`1.62* 10^(-2)` ohm

Therefore, the resistance of copper wire is,
`1.62* 10^(-2)` Ω