Question

Imagine the following genotype frequencies in a population: p2 = 0.49, 2pq = 0.42, q2 = 0.09. Now assume that there is nonrandom mating where individuals with one genotype will only mate with individuals that also have their genotype. Assume this pattern of mating goes on until the frequency of heterozygotes is effectively zero. What will the frequency of allele p be in the population? 0.49 0.91 0.3 1.0 0.7

Answer 1

The frequency of allele p in the population can be calculated using the Hardy-Weinberg equation: p² + 2pq + q² = 1. Given the genotype frequencies, we can determine that the frequency of allele p is 0.7.

Step-by-step explanation:

The frequency of allele p in the population can be calculated using the Hardy-Weinberg equation: p² + 2pq + q² = 1. In this equation, p represents the frequency of allele A, and q represents the frequency of allele a. In the given question, we are given the genotype frequencies: p² = 0.49, 2pq = 0.42, and q² = 0.09. Since p² represents the frequency of homozygous dominant individuals, we can directly equate it to 0.49. Solving this equation, we find that p = 0.7. Therefore, the frequency of allele p in the population is 0.7.

Answer 2

frequency of allele = Square root (p^2)

= Square root (0.49)

= 0.7