Answer: C) x = 3, (x = 2 is an extraneous solution)
Explanation:
-
=

-
=

Restrictions: Denominator cannot equal zero (x - 1 ≠ 0) and (x - 2 ≠ 0), so x ≠ 1 and x ≠ 2
-
=

x(x - 2) - 1(x - 1) = 2x - 5
x² - 2x - x + 1 = 2x - 5
x² - 3x + 1 = 2x - 5
-2x + 5 -2x + 5
x² - 5x + 6 = 0
(x - 2)(x - 3) = 0
x - 2 = 0 x - 3 = 0
x = 2 x = 3
NOTE: x = 2 is an extraneous solution because it is one of the restricted values.