Answer:
We can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:
Explanation:
From the coordinate plane, we can clearly identify that:
- Sandy's Hotel is located at the point (-8, 9)
- Trader Joes' Store is located at the point (-4, 2)
The distance from Sandy's Hotel to Trader Joes' Store can be calculated such as:
![d=\:√(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/opwf4092p0q2fufhuhssxovpj8oz4wxu5m.png)
The distance between (-8, 9) and (-4, 2)
![d=√(\left(-4-\left(-8\right)\right)^2+\left(2-9\right)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mzio8fmieddrs6m2prbu8hil2q7kw4a0c9.png)
![=√(\left(-4+8\right)^2+\left(2-9\right)^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/opb1sb13ongrw6g2oc33smfz9bdp5iskw8.png)
![=√(16+49)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ow8shb3v62n2lodvhmxfj6xyof9co51bz7.png)
![=√(65)](https://img.qammunity.org/2022/formulas/mathematics/high-school/3u40ndobls54jf9wffczk29xd398p0n1eg.png)
miles
Therefore, we can conclude that the distance from Sandy's Hotel to Trader Joes' Store is: