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Pls help due ASAP....
Pls show workings.

Pls help due ASAP.... Pls show workings.-example-1
User Joebeeson
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1 Answer

4 votes

Answer:

We can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:

  • d = 8.06 miles

Explanation:

From the coordinate plane, we can clearly identify that:

  • Sandy's Hotel is located at the point (-8, 9)
  • Trader Joes' Store is located at the point (-4, 2)

The distance from Sandy's Hotel to Trader Joes' Store can be calculated such as:


d=\:√(\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2)

The distance between (-8, 9) and (-4, 2)


d=√(\left(-4-\left(-8\right)\right)^2+\left(2-9\right)^2)


=√(\left(-4+8\right)^2+\left(2-9\right)^2)


=√(4^2+7^2)


=√(16+49)


=√(65)


=8.06 miles

Therefore, we can conclude that the distance from Sandy's Hotel to Trader Joes' Store is:

  • d = 8.06 miles
User Jacquen
by
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