Answer: The correct width is given by (C) 10x - 6.
Step-by-step explanation: Given that the area 'A' and the length 'l' of a rectangle r as follows:
![A=120x^2+78x-90,\\\\l=12x+15.](https://img.qammunity.org/2019/formulas/mathematics/high-school/abwk0kfu9y8s8fh77j68spbrxj4u2tjg1y.png)
We are to find the width, 'w' of the rectangle.
The AREA of a rectangle is equal to the product of its length and breadth.
So, in the given rectangle, we have
![A=l* w\\\\\Rightarrow w=(A)/(l).](https://img.qammunity.org/2019/formulas/mathematics/high-school/oluhbyofoi3odg37gfqzvqcs2ra9jd5oos.png)
Therefore, the width is given by the quotient of the area and the length of the rectangle.
The width can be calculated as follows:
![w\\\\=(A)/(l)\\\\=(120x^2+78x-90)/(12x+15)\\\\\\=(10x(12x+15)-6(10x+15))/(12x+15)\\\\\\=((10x-6)(12x+15))/((12x+15))\\\\=10x-6.](https://img.qammunity.org/2019/formulas/mathematics/high-school/skrelo17hku031suw25xae5yorgm6xektv.png)
Therefore, width of the rectangle, w = 10x - 6.