menu
QAmmunity.org
Login
Register
My account
Edit my Profile
Private messages
My favorites
Register
Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question
Use the balanced chemical equation to work the following problem. 2C4H10 + 13O2 → 8CO2 + 10H2O How many grams of CO2 (molar mass = 44.01 g/mol) would be formed from the total reaction of 5.00 g of C4H10
asked
Oct 13, 2019
229k
views
4
votes
Use the balanced chemical equation to work the following problem.
2C4H10 + 13O2 → 8CO2 + 10H2O
How many grams of CO2 (molar mass = 44.01 g/mol) would be formed from the total reaction of 5.00 g of C4H10 (molar mass = 58.1 g/mol)?
15.1 g
0.947 g
0.114 g
26.4 g
Chemistry
high-school
Peter Bernier
asked
by
Peter Bernier
5.7k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
2
Answers
2
votes
Answer:
15.1 is the correct answer just did this quiz
Omarion
answered
Oct 16, 2019
by
Omarion
5.9k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
6
votes
the answer is 0.947 g CO2
Shyamkkhadka
answered
Oct 18, 2019
by
Shyamkkhadka
6.1k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.
6.5m
questions
8.6m
answers
Other Questions
When weak acids react with strong bases, the H+ from the weak acid is transferred to the: metal of the strong base to form a metal hydride OH− from the strong base to form water and a salt salt that is
True or false: in the water cycle, water returns to Earth as condesation, usually in the form of rain or snow.
How many moles of ca(no32 are in 400 ml of a 0.80 m calcium nitrate solution?
How do the number of daylight hours affect temperature
Which of the following is the correct scientific notation for 0.000451 g? 4.5 x 10-3 4.5 x 10-5 4.51 x 10-4 45.1 x 10-4
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search QAmmunity.org