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A sales analyst listed the probabilities of profits and losses in dollars for a certain company. Find the mean for the probability distribution.

A sales analyst listed the probabilities of profits and losses in dollars for a certain-example-1
User Hmnzr
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2 Answers

3 votes

Answer:

The answer is 69.25

Step-by-step explanation:

User Ludovic Feltz
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2 votes

Answer: The mean for the probability distribution will be 69.25.

Step-by-step explanation:

Since we given that


At\ x_1= -500 ,P(x) = 0.076\\


At\ x_2= -250,P(x)= 0.191\\


At\ x_3=0, P(x)= 0.265\\


At\ x_4=250 , P(x)= 0.316\\


At\ x_5=500 , P(x)= 0.152\\

As we know the formula for expectation of x i.e. known as mean for the probability distribution,


E(x)=x\sum_(1)^(5) P(x)

So, we apply this formula in our case,


-500* 0.076+(-250)* 0.191+0* 0.265+250* 0.316+500* 0.512=69.25


\mu = 69.25

Hence, the mean for the probability distribution will be 69.25.



User Harinarayanan K S
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