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Find x so the distance between (x,2) and (1,4) is square root 13.

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The formula of a distance between two points:


d=√((x_2-x_1)^2+(y_2-y_1)^2)

We have the points (x, 2) and (1,4) and the distance d = √13.

Substitute:


√((1-x)^2+(4-2)^2)=√(13)\\\\√((1-x)^2+2^2)=√(13)\\\\√((1-x)^2+4)=√(13)\iff(1-x)^2+4=13\qquad|-4\\\\(1-x)^2=9\iff1-x=\pm\sqrt9\\\\1-x=-3\ \vee\ 1-x=3\qquad|-1\\\\-x=-4\ \vee\ -x=2\qquad|\text{change the signs}\\\\\boxed{x=4\ \vee\ x=-2}

Answer: x = -2 or x = 4.

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