Answer:
Conclusion:
Explanation:
Given
We know that the diagonals of a parallelogram bisect each other.
Therefore,
Given RT = x and TP = 5x-28, so
x = 5x-28
5x = x+28
5x-x = 28
4x = 28
divide boh sides by 4
4x/4 = 28/4
x = 7
Thus, the value of x = 7
Similarly,
QT = TS
Given QT = 5y and TS = 2y+12, so
5y = 2y+12
5y-2y = 12
3y = 12
divide both sides by 3
3y/3 = 12/3
y = 4
Thus, the value of y = 4
Conclusion: