Question

The table below shows the distance d(t) in meters that an object travels in t seconds: t (seconds) d(t) (meters) 2 64 4 256 6 576 8 1024 What is the average rate of change of d(t) between 2 seconds and 6 seconds, and what does it represent? 128 m/s; it represents the average speed of the object between 2 seconds and 6 seconds 80 m/s; it represents the average speed of the object between 2 seconds and 6 seconds 128 m/s; it represents the average distance traveled by the object between 2 seconds and 6 seconds 80 m/s; it represents the average distance traveled by the object between 2 seconds and 6 seconds

Answer 1

128 feet per second.

Explanation:

s = 2 ⇔ t = 6

Follow: r = (576 - 64) ÷ (t - s)

r = 512 / 4 ⇒ 128ft/s

Hope This Helps :)

Answer 2

We have given a table for time and distance traveled .

Time (t) :- 2 4 6 8

Distance traveled d(t) : - 64 256 576 1024

We need to find average rate of change of d(t) between time 2 seconds

and 6 seconds .

We know that the formula for average rate of change is :-

Change in distance

Average Rate of change = ---------------------------------------

Change in time

Distance traveled at t = 2 is 64 meters .

Distance traveled at t = 6 is 576 meters .

Change in distance is 576 - 64 = 512 meters .

Change in time is 6 - 2 = 4 seconds .

change in distance 512 meter

Average Rate of change = ----------------------------- = -------------------------

Change in time 4 seconds

= 1 28 meter/ second.

Thus Average rate of change is 128 m/s .

This is the change in distance with respect to time .

This represent the speed .

Thus (A) is the correct option .

128 m/s ; it represents the average speed of the object between 2 seconds and 6 seconds .