13.0k views
7 votes
Find the value of the polynomial 2x^3y^3+3xy-3x^3y^3+x^2y-xy+2x^2y for x=-1 and y=2

1 Answer

6 votes

Answer:

10

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Explanation:

Step 1: Define

2x³y³ + 3xy - 3x³y³ + x²y - xy + 2x²y

x = -1

y = 2

Step 2: Evaluate

  1. Substitute: 2(-1)³(2)³ + 3(-1)(2) - 3(-1)³(2)³ + (-1)²(2) - (-1)(2) + 2(-1)²(2)
  2. Exponents: 2(-1)(8) + 3(-1)(2) - 3(-1)(8) + 1(2) - (-1)(2) + 2(1)(2)
  3. Multiply: -16 - 6 + 24 + 2 - (-2) + 4
  4. Simplify: -16 - 6 + 24 + 2 + 2 + 4
  5. Subtract: -22 + 24 + 2 + 2 + 4
  6. Add: 2 + 2 + 2 + 4
  7. Add: 4 + 2 + 4
  8. Add: 6 + 4
  9. Add: 10
User Ibarrond
by
4.0k points