Question

How many moles of gas does it take to occupy 120 L at a pressure of 233 kPa and a temperature of 340 K?

A. 6.4 moles
B. 7.7 moles
C. 8.6 moles
D. 9.9 moles

Answer 1

A would be correct have a nice day.

Answer 2

The correct answer is option D.

Step-by-step explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of gas = 233 kPa

1 atm = 101.325 kPa

`233kPa=(233)/(101.325) atm=2.30 atm`

V = Volume of gas = 120 L

n = number of moles of gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 340 K

Putting values in above equation, we get:

`2.30 atm* 120L=n* (0.0821L.atm/mol.K)* 340K\\\\n=9.88 mole\approx 9.9 mole`