Question

A certain shade of blue has a frequency of 7.16 × 1014 Hz. What is the energy of exactly one photon of this light?

Answer 1

Answer : The energy of one photon of light is
`4.747* 10^(-19)J`.

Solution : Given,

Frequency =
`7.16* 10^(14)Hz=7.16* 10^(14)s` (1Hz = 1 second period)

Formula used :

`E=h\\u`

where,

E = energy

h = Planck's constant =
`6.63* 10^(-34)J/s`

`\\u` = frequency

Now put the given values in above formula, we the value for energy of one photon.

`E=(6.63* 10^(-34)J/s)* (7.16* 10^(14)s)=4.747* 10^(-19)J`

Therefore, the energy of one photon of light is
`4.747* 10^(-19)J`.