How to solve exponential equations with constant prime numbers or number whos fractors are primes? Example: 3^x+2+3^x−3=244

asked Jul 24, 2023 76.2k views

23 votes

How to solve exponential equations with constant prime numbers or number whos fractors are primes?

Example: 3^x+2+3^x−3=244

3.9k points

Please log in or register to add a comment.

13 votes

Answer:

x=3

Explanation:

3^(x+2)+3^(x-3)=244

3^x3^2+(3^x)/(3^3) =244

3^x(9+(1)/(27))=244

3^x((244)/(27))=244

3^x=27

x=log_3(27)

x=3

Nifoem Bar answered Jul 31, 2023

3.5k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

3.6m questions

4.6m answers