Question

How to solve exponential equations with constant prime numbers or number whos fractors are primes?

Example: 3^x+2+3^x−3=244

Answer 1

`x=3`

Explanation:

`3^(x+2)+3^(x-3)=244`

`3^x3^2+(3^x)/(3^3) =244`

`3^x(9+(1)/(27))=244`

`3^x((244)/(27))=244`

`3^x=27`

`x=log_3(27)`

`x=3`