Question

A car goes from rest to a velocity of 108 km/h north in 10s what is the car's acceleration in m/s2

Answer 1

initial velocity of the car given as

`v_i = 0`

final velocity is given as

`v_f = 108 km/h`

as we know that

`1 km/h = 0.277 m/s`

now we can convert final speed into m/s

`v_f = 108 * 0.277 = 30 m/s`

now acceleration is rate of change in velocity

`a = (v_f - v_i)/(t)`

`a = (30 - 0)/(10)`

`a = 3 m/s^2`

so the acceleration of the car is 3 m/s^2