Question

A force of 42N is needed to start a box sliding across the floor. The weight of the box is 55N.

a. How large is the force of the friction?

b. Is the frictional force statice or kinetic?

c. What is the coefficient of friction?


PLEASE EXPLAIN HOW YOU GOT THE ANSWER

Answer 1

Step-by-step explanation:

It is given that,

Force applied to the box, F = 42 N

Weight of the box, W = 55 N

(a) Let f is the force of the friction acting on the box. The force of friction always opposes the motion of an object. It always equal to the applied force as :

f = -F = -42 N

(b) The frictional force is kinetic in nature because when the force is applied to the box it starts to move.

(c) Let
`\mu` is the coefficient of friction. It is given by :

`\mu=(f)/(N)`

`\mu=(42)/(55)`

`\mu=0.76`

Hence, this is the required solution.